Find the minimum coefficient of friction needed to prevent slipping. I have already calculated the acceleration of the sphere and the magnitude of the friction force on the sphere in previous parts. I didn't think I needed to use torque here, because I got the same answer that way as well.What is the coefficient of static friction if it takes 34 N of force to move a box that weighs 67 N? What force of friction can it exert on the ground? What is the maximum acceleration of this car? In what minimum distance could it stop from 27 m/s?Coefficient of friction can be defined as the ratio of the force of friction between two bodies and the force pressing them together [26]. They observed for a constant FA particle size and percentage of FA, a rise in load and speed decreased the coefficient of friction.Intuitively, friction is the that property of matter that makes it "sticky". Think for example of a solid object, for simplicity we will make it 0-dimensional If a larger tangential force is applied in the direction of motion, the frictional force does not increase (except for variations in the coefficient of friction)...Suppose If a car takes a banked curve at less than the ideal speed, friction is needed to keep it from sliding toward the inside of the curve. Using formula for coefficient of friction. Put the value into the formula.
Friction
Minimum coefficient of friction needed? Please answer part (b) of question #9! m/s (b) What is the minimum coefficient of friction needed for a frightened driver to take the same curve at 25.0 km/h?The friction theory and friction coefficients at different conditions for various of materials like ice, aluminum, steel, graphite and other The friction force is the force exerted by a surface when an object moves across it - or makes an effort to move across it. The frictional force can be expressed as.F (friction), u (coefficient of friction), and N (normal). So you first need to solve for the normal by using Newton's second law. friction is the resisting force which oppose the relative motion of two body.cofficient of friction is the ratio of frictional force and normal force of body on surface.thus...You can find the minimum coefficient of static friction between two materials by conducting an inclined plane experiment with the materials. Physicists distinguish between static friction, which acts to keep a body at rest, and kinetic friction, which acts to slow down its motion once it begins moving.
Friction Coefficient - an overview | ScienceDirect Topics
Mathematically, frictional force can be expressed asFf= ? N, where Ff = frictional force (N, lb), ? = static (?s) or kinetic (?k) frictional coefficient We have written many articles about the coefficient of friction for Universe Today. Here's an article about friction, and here's an article about aerobraking.I just need some help understanding this. Yes, it is possible for a coefficient of friction to be greater than 1. One particular example is rubber on rubber, which, according to this, has a static coefficient of friction of 1.16. Coefficient of friction is a ratio of frictional force to gravitational weight, effectively.Friction coefficient table of solid lubricants, metals, plastics and anti-friction materials Friction coefficient table for various material pairs in atmosphere and vacuum (see the definition of friction coefficient) is shown below. The data was collected from various sources .Part B asks "What is the minimum coefficient of friction needed for a frightened driver to take the same curve at 25 km/h or 6.9444 m/s. Lastly, you may need to solve two inequalities, be careful to preserve the signs to make sure you find the correct condition. (not the maximum coefficient of...friction is needed to keep it from sliding toward the inside of the. curve (a real problem on icy mountain roads). (a) Calculate the ideal speed to take a 135-m radius curve. banked at 18.0�. (b) What is the minimum coefficient of friction needed for a. frightened driver to take the same curve at 15.0 km/h?
Updated December 14, 2020
By Chris Deziel
Friction is a pressure that opposes motion. Physicists distinguish between static friction, which acts to stay a body at relaxation, and kinetic friction, which acts to slow down its motion once it begins moving. The pressure exerted via static friction (Fs) is proportional to the perpendicular pressure exerted through a frame against the surface alongside which it's transferring, which is referred to as the customary force (FN). The proportionality issue is called the coefficient of static fraction, which is in most cases denoted through the Greek letter mu with a subscript s (µs). The mathematical relation is:
F_s=\mu_s F_N
This coefficient relies on the traits of the two surfaces that are involved with every other. It has been tabulated for a number of other fabrics. If you'll't find µs for the materials you might be using, you can decide it with a easy experiment.
TL;DR (Too Long; Didn't Read)TL;DR (Too Long; Didn't Read)
To find the minimum coefficient of static friction between two materials, assemble an incline plane from one of the fabrics and place a frame produced from the different subject material on it. Increase the attitude of the incline until the frame starts to slide. The tangent of the attitude is the coefficient of friction.
Use an Inclined Plane
A easy approach to resolve µs is to place the object in question on an prone airplane made of the similar subject material as the floor you are finding out. Gradually build up the angle of the incline until the object starts to slip. Record that attitude. You can in an instant find µs as it is equal to the tangent of the perspective. Here's why:
As you elevate the incline, the drive of gravity performing on a body of mass m has a horizontal and a vertical component. Applying Newton's Law to each and every of those just sooner than the body starts to transport, you find the horizontal part (which acts in the x-direction) to be Fx = max. The same is true in the y course: Fy = would possibly.
The acceleration in the x-direction, max, is equivalent to the drive of gravity, which is mass occasions acceleration because of gravity (g) instances the sine of the attitude (ø) formed at the fulcrum of the incline. Since the body is now not moving, this is equal to the opposing force of static friction, and you'll be able to write:
1. mg\sin\theta=F_s
The y-direction part of power, might, is equivalent to the cosine of the perspective times the mass occasions the acceleration because of gravity, and this should equivalent the customary force, since the body is not transferring,
2. F_N=mg\cos\theta
Remember that Fs = µsFN. Substitute for Fs in equation (1):
mg\sin\theta=\mu_s F_N
and use the equality to equation (2) to substitute for FN:
mg\sin\theta=\mu_s mg \cos\theta
The time period "mg" cancels from both sides:
\mu_s=\frac\sin\theta\cos\theta=\tan\theta
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